Class 9 Science Chapter 3 – Atoms and Molecules Intext Questions and Answers | NCERT Solutions

Understanding the fundamental concepts of atoms and molecules is essential for building a strong base in Chemistry. In this chapter, you learn how matter is made up of tiny particles and how these particles combine to form different substances.

To help students prepare better, we have provided NCERT Class 9 Science – Atoms and Molecules Intext Questions and Answers in a clear and easy-to-understand format. These solutions will help you revise important concepts, score well in exams, and strengthen your overall understanding of the chapter.


Ch:-3 – ATOMS AND MOLECULES

Intext Solution

Ques 1:- 7. In a reaction 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid . The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate.Show that these observations are in agreement with the law of conservation of mass.

Sodium carbonate + ethanoic acid → sodium ethanoate + Carbon dioxide + water.

Ans :- In the given reaction, sodium carbonate reacts with ethanoic acid to produce sodium ethanoate, carbon dioxide and water.

Now,
Mass of sodium carbonate: 5.3 g
Mass of ethanoic acid: 6 g

Total mass of reactant = (5.3 + 6) g = 11.3 g

Also,
Mass of sodium ethanoate = 8.2 g
Mass of carbon dioxide = 2.2 g
Mass of water = 0.9 g

Total mass of Product = (8.2 + 2.2 + 0.9) g = 11.3 g

Therefore Total mass of reactant = Total mass of Product

Hence the given observations are in agreement with the law of conservation of mass.


Ques 2:- Hydrogen and oxygen combine in the ratio of 1 : 8 by mass to form water.What mass of oxygen gas would be required to react completely with 3 g of hydrogen gas ?

Ans :- Given Hydrogen and oxygen combine in the ratio of 1 : 8 by mass to form water (H2O).

Its mean that 1 g of hydrogen gas will reacts completely with 8 g of Oxygen.

∴ 3 g of hydrogen gas will reacts completely with 8 × 3 = 24 g of Oxygen.

Hence 24 g of oxygen gas would be required to react completely with 3 g of hydrogen gas.


Ques 3:- Which postulate of Dalton’s atomic theory is the result of the law of conservation of mass ?

Ans:-The postulate of Dalton’s atomic theory which is a result of the law of conservation of mass is "Atoms are indivisible particles, which can neither be created nor destroyed in a chemical reaction".


Ques 4:- Which postulate of Dalton’s atomic theory can explain the law of definite proportions ?

Ans:- The postulate of Dalton’s atomic theory which can explain the law of definite proportion is "The relative number and kind of atoms in a given compound remain constant ".


Page 30

Ques 1:- Define atomic mass unit.

Ans:- The atomic mass unit is defined as the mass equal to 1/12 th the mass of ¹²₆C atom. It is written as "U".







Ques 2:- Why is it not possible to see an atom with naked eyes?

Ans:- The size of an atom is so small that it is not possible to see it with naked eyes. Also, atom of an element does not exist independently.


Page 34

Ques 1:- Write down the formula of

Ans:- (i) Sodium oxide
(ii) Aluminium chloride
(iii) Sodium sulphide
(iv) Magnesium hydroxide.

Ans (i) :- Formula of Sodium oxide

Formula: - Na2O

Ans (ii) :- Formula of Aluminium chloride

Formula: - AlCl3

Ans (iii) :- Formula of Sodium sulphide

Formula: - Na2S

Ans (iv) :- Formula of Magnesium hydroxide

Formula: - Mg(OH)2

Ques 2:- Write down the name of compounds represented by the following formulae :

Al2(SO4)3 , CaCl2 , K2SO4 , CaCO3

Ans:-

Chemical Formula Name of Compound
(i) Al2(SO4)3 Aluminium sulphate
(ii) CaCl2 Calcium chloride
(iii) K2SO4 Potassium sulphate
(iv) KNO3 Potassium nitrate
(v) CaCO3 Calcium carbonate

Ques 3:- What is meant by the term chemical formula ?

Ans:- The chemical formula of a compound is a symbolic representation of its composition.

For example chemical formula of carbon dioxide is CO2, we come to know that one carbon atom and two oxygen atoms are chemically bonded together to form one molecule of the compound, carbon dioxide.

Ques 4:- How many atoms are present in a

(i) H2S molecule , and
(ii) PO4 ion ?

Ans :- (i) In a H2S molecule, three atoms are present;
two of hydrogen and one of sulphur.

(ii) In a PO4 ion, five atoms are present;
one of phosphorus and four of oxygen.

Page 35

Ques 1:- Calculate the molecular masses of

H2, O2, Cl2, CO2, CH4, C2H6, C2H4, NH3, CH3OH,

(i) Molecular mass of H2 = 2 × Atomic mass of H

= 2 × 1u
= 2u

(ii) Molecular mass of O2 = 2 × Atomic mass of O

= 2 × 16u
= 32u

(iii) Molecular mass of Cl2 = 2 × Atomic mass of Cl

= 2 × 35.5u
= 71u

(iv) Molecular mass of CO2 = 2 × Atomic mass of C + 2 x Atomic mass of O

= 12u + 2 x 16u
= 12u + 32u
= 44u

(v) Molecular mass of CH4 = Atomic mass of C + 4 x Atomic mass of H

= 12u + 4 x 1u
=12u + 4u
= 16u

(vi) Molecular mass of C2H6 = 2 x Atomic mass of C + 6 x Atomic mass of H

= 2 x 12u + 6 x 1u
= 24u + 6u
= 30u

(vii) Molecular mass of C2H4 = 2 x Atomic mass of C + 4 x Atomic mass of H

= 2 x 12u + 4 x 1u
= 24u + 4u
= 28u

(viii) Molecular mass of NH3 = Atomic mass of N + 3 x Atomic mass of H

= 14u + 3 x 1u
= 14u + 3u
= 17u

(ix) Molecular mass of CH3OH = Atomic mass of C + 3 x Atomic mass of H + Atomic mass of O + Atomic mass of H

= 12u + 3 x 1u + 16u + 1u
= 12u + 3u + 16u + 1u
= 32u

Ques 2:- Calculate the formula unit masses of :

ZnO2 , Na2O , K2CO3
given atomic masses of Zn = 65 u , Na = 23 u , K = 39 u , C = 12 u , and O = 16 u .

Ans:-

(i) Atomic mass of Zn = 65u
Atomic mass of O = 16u

Formula unit mass of ZnO = Atomic mass of Zn + Atomic mass of O

= 65 + 16

Formula unit mass of ZnO = 81 u

(ii) Atomic mass of Na = 23u
Atomic mass of O = 16u

Formula unit mass of Na2O = 2 x Atomic mass of Na + Atomic mass of O

= 2 x 23 + 16 =62

Formula unit mass of Na2O = 62u

(iii) Atomic mass of K= 39u
Atomic mass of C = 12u
Atomic mass of O= 16u

Formula unit mass of K2CO3 = 2 x Atomic mass of K + Atomic mass of C + 3 x Atomic mass of O

= 2 x 39 + 12 + 3 x 16 = 138

Formula unit mass of K2CO3 = 138 u


Conclusion

The chapter “Atoms and Molecules” helps us understand how matter is made up of tiny particles and how these particles combine in fixed ratios to form different substances.By solving the intext questions, students become familiar with key concepts such as atomic mass,molecular mass, chemical formulas, laws of chemical combination, and the idea of moles.These concepts form the foundation of chemistry and are essential for understanding reactions,calculations, and the composition of various chemical compounds.

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